Which of the following statement is correct?

${\mathrm{sp}}^3$ hybridization exists in diamond and  ${\mathrm{sp}}^2$ in graphite.

Each carbon atom in a diamond forms four sigma bonds with four other carbon atoms. As a result, carbon hybridization is ${\mathrm{sp}}^3$

Each carbon atom in graphite forms three sigma bonds with three other carbon atoms. hence, ${\mathrm{sp}}^2$ hybridization.

The hybridization of the carbon atom in acetylene, graphite, and diamond is ${\mathrm{sp}}^3$ and ${\mathrm{sp}}^2$, respectively.