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Which of the following statement is correct, about "on passing $H_{2} S$ gas through acidified $K_{2} {Cr}_{2} O_{7}$ solution"?

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Milky colour of the solution is due to ${SO}_{4}^{2 -}$ .

Milky colour of the solution is due to ${Cr}^{3 +}$ .

Milky colour of the solution is due to ${SO}_{3}^{2 -}$ .

Milky colour of the solution is due to $S$ .

answer is C.

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Detailed Solution

On passing hydrogen sulfide gas through potassium dichromate milky colour of the solution is obtained. The solution is due to sulphur.

$K_{2} {Cr}_{2} O_{7} + 3 H_{2} S + 4 H_{2} {SO}_{4} \to 3 S + K_{2} {SO}_{4} + {Cr}_{2} {({SO}_{4})}_{3} + 7 H_{2} O$

Hence correct option is C.

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