Which of the following statement is correct with respect to bond angle?

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The Cl-N-0 angle in NOCI is more than 120°

The F-S-F angle in SF 2 is more than 109°28'

The F-Kr-F angle in ${KrF}_{4}$ is 90°

The H-N-N angle in $N_{2} H_{2}$ is approximately $180 °$

answer is C.

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Detailed Solution

Bond angles for the KrF4 are at F-Kr-F 90° and F-Kr-F 180°. All of the fluorine atoms are arranged perpendicular to the krypton atom due to square planer geometry. due to the fluorine atom's different equatorial and axial positions. At 90° and 180°, the KrF4 molecule displays two distinct bond angles.

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