Which of the following statement is/are correct :

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A charged particle enters a region of uniform magnetic field at an angle $85^{0}$ to magnetic lines of force. The path of the particle is a circle.

There is no change in the energy of a charged particle moving in a magnetic field although magnetic force acts on it.

An electron and proton are moving with the same kinetic energy along the same direction. When they pass through uniform magnetic field perpendicular to their direction of motion, they describe circular path.

Two electrons enter with the same speed but in opposite direction in a uniform transverse magnetic field. Then the electrons describe two circles of the same radius , but they move in the opposite direction.

answer is B, C, D.

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Detailed Solution

In option (1) , path of the particle will be helix .

Magnetic force acting on a charged particle moving in a magnetic field is given by , $\vec{F} = (- e) \vec{v} \times \vec{B} . W h e n \vec{B} i s p e r p e n d i c u l a r t o \vec{v}, p a t h d e s c r i b e d b y t h e p a r t i c l e i s a c i r c l e .$

Also , for a charged particle magnetic force is always perpendicular to the direction of motion of the particle and hence work done by it is always zero . As a result spedd of the particle remains unchanged .

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