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Q.
Which of the following statement (s) is/are correct?
(A)The pH of 1 x 10-8M HCl solution is 8
(B)The conjugate base of H3PO4- is HPO42-
(C) Kw increases with increase in temperature
(D) When a solution of a weak monoprotic acid is titrated against a strong base At half
neutralization point,
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a
(A), (B), (C)
b
(A), (D)
c
(B), (C), (D)
d
(B), (C)
answer is B.
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Detailed Solution

(A) The pH of 1×10−8 M HCl solution is 8.
This statement is incorrect. For a strong acid like HCl, the concentration of H+ ions will be the same as the concentration of the acid, i.e., 1×10−8 M. The pH can be calculated using the formula:
pH=−log[H+]=−log(1×10−8)=8
However, because the concentration is so low, it approaches the range where water auto-ionization becomes significant. In this case, the solution pH will be slightly higher than 7, but not exactly 8.
(B) The conjugate base of is .
This statement is correct. The conjugate base of an acid is formed when it loses one H+ ion:
→ + H+
(C) Kw increases with an increase in temperature.
This statement is correct. The ion product of water, Kw, increases with increasing temperature. This is because the auto-ionization of water is an endothermic process, meaning it absorbs heat:
H2O⇌H+ + OH−
As the temperature increases, the equilibrium shifts towards the formation of more H+ and OH− ions, leading to an increase in Kw.
(D) When a solution of a weak monoprotic acid is titrated against a strong base at the half-neutralization point, pH=pKa
This statement is incorrect. At the half-neutralization point, the concentration of the weak acid ([HA]) is equal to the concentration of its conjugate base ([A-]). According to the Henderson-Hasselbalch equation:
pH=pKa+log
At the half-neutralization point, the ratio of [A-] to [HA] is 1, so the equation becomes:
pH=pKa + log(1) =pKa
Therefore, the correct answer is:
(B) and (C) are correct.