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Q.

Which of the following statement (s) is/are correct?
(A)The pH of 1 x 10-8M HCl solution is 8
(B)The conjugate base of H3PO4- is HPO42-
(C) Kw increases with increase in temperature
(D) When a solution of a weak monoprotic acid is titrated against a strong base At half
neutralization point, pH=12pKa

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a

(A), (B), (C)

b

(A), (D)

c

(B), (C), (D)

d

(B), (C)

answer is B.

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Detailed Solution

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(A) The pH of   1×10−8 M HCl solution is 8.

This statement is incorrect. For a strong acid like HCl, the concentration of H+ ions will be the same as the concentration of the acid, i.e.,  1×10−8 M. The pH can be calculated using the formula:

pH=−log⁡[H+]=−log⁡(1×10−8)=8

However, because the concentration is so low, it approaches the range where water auto-ionization becomes significant. In this case, the solution pH will be slightly higher than 7, but not exactly 8.

(B) The conjugate base of H2PO4- is HPO42-.

This statement is correct. The conjugate base of an acid is formed when it loses one H+ ion:

H2PO4-HPO42- + H+

(C) Kw increases with an increase in temperature.

This statement is correct. The ion product of water, Kw, increases with increasing temperature. This is because the auto-ionization of water is an endothermic process, meaning it absorbs heat:

H2O⇌H+ + OH

As the temperature increases, the equilibrium shifts towards the formation of more H+ and OH ions, leading to an increase in Kw.

(D) When a solution of a weak monoprotic acid is titrated against a strong base at the half-neutralization point, pH=12pKa

This statement is incorrect. At the half-neutralization point, the concentration of the weak acid ([HA]) is equal to the concentration of its conjugate base ([A-]). According to the Henderson-Hasselbalch equation:

pH=pKa+log⁡A-HA

At the half-neutralization point, the ratio of [A-] to [HA] is 1, so the equation becomes:

pH=pKa + log(1) =pKa

Therefore, the correct answer is:

(B) and (C) are correct.

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