Which of the following statement(s) is(are) correct about the spectrum of hydrogen atom ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

The ratio of the longest wave length to the shortest wavelength in Balmer series is 9/5.

There is an overlap between the wave length ranges of Balmer and Paschen series.

The wavelength of lyman series are given by $(1 + \frac{1}{m^{2}}) λ_{0}$ ; where $λ_{0}$ is the shortest wavelength of Lynan series and m is an integer.

The wavelength ranges of Lyman and Balmer series do not overlap .

answer is A, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\frac{1}{λ} = R (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$

Lyman $\Rightarrow 911 A^{0} - 1215 A^{0}$
Balmer $\Rightarrow 3645 A^{0} - 6562 A^{0}$
Paschen $\Rightarrow 8202 A^{0} - 18747 A^{0}$
Balmer : $λ_{\max} = \frac{36}{5 R}$
$λ_{\min} = \frac{4}{R}$
Lyman : $\frac{1}{λ} = R (\frac{1}{1} - \frac{1}{n_{2}^{2}})$
$λ = (\frac{n_{2}^{2}}{n_{2}^{2} - 1}) \frac{1}{R} = (1 + \frac{1}{n_{2}^{2} - 1}) \frac{1}{R} λ = (1 + \frac{1}{m^{2}}) λ_{0}$