Q.

Which of the following statement(s) is/are correct?

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a

Lattice energies of alkali metal super oxides are less than those of the peroxides

b

Order of ionic radii O2<O2<O22

c

Thermal stability of super oxides increases with increase in the size of alkali metal ion

d

Thermal stability of alkali metal oxides decreases down the group

answer is A, B, C, D.

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Detailed Solution

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The bond order in O2 is 1.5 while that of O22 is 1.0. So bond length in O2 is less than in O22. Thus O22 is larger than O2. O 2 is smaller than both O2&O22(O2=126pm,O22=180pm and O2=163pm)

A) L.E  αZ+×Zrc+ra. As the size of cation (rc) increases down the group L.E decreases thus stability decreases

B) Since Z is 1 in O2 (super oxide ion ) 2 in O22 (peroxide ion) the LE of super oxides will be less than peroxides

D) Thermal stability of super oxides is a combined effect of lattice energies of oxides, super oxide and decomposition energy of super oxide. Stability of super oxides increases down the group.

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