Which of the following statements about anhydrous aluminium chloride is correct?

Aluminum chloride (AlCl₃) easily undergoes hydrolysis because of the high hydration energy of Al³⁺. AlCl₃ forms aluminum hydroxide and HCl, when comes in contact with water. This produced HCl produces white fumes when comes in contact with air.

${\mathrm{AlCl}}_3+3{\mathrm{H}}_2\mathrm{O}⟶\mathrm{Al}(\mathrm{OH}{)}_3+\underset{\mathrm{White} \mathrm{fumes}}{3\mathrm{HCl}\uparrow }$

AlCl₃ is an electron-deficient because Al has an incomplete octet, therefore in a vapor state and non-polar solvents, it exists as Al₂Cl₆ where Al of one AlCl₃ forms a dative bond with Cl of another AlCl₃, where Cl shares its electron pair in the dative bond formation.

AlCl₃ also forms when the aluminum oxide is heated with sulfur chloride and chlorine gas.
$4{\mathrm{Al}}_2{\mathrm{O}}_3+3{\mathrm{S}}_2{\mathrm{Cl}}_2+9{\mathrm{Cl}}_2\stackrel{∆}{\to }8{\mathrm{AlCl}}_3+6{\mathrm{SO}}_2\uparrow$
This indicates that the given statements are correct.