Q.

Which of the following statements are correct with respect to [NiCl4]2 and [Ni(PPh3)2Cl2]

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a

[NiCl4]2is square planar

b

In both cases Ni undergoes dsp2 hybridisation

c

[Ni(PPh3)2Cl2]  is  square planar

d

[Ni(PPh3)2Cl2] is  tetrahedral

answer is B.

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Detailed Solution

Cl is weak ligand so no pairing of electrons take place. so [NiCl4]2 is tetrahedral. pph3 group is bulkier one so it favours tetrahedral geometry, through pph3 is strong field ligand.

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Which of the following statements are correct with respect to [NiCl4]2− and [Ni(PPh3)2Cl2]?