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Q.

Which of the following statements are incorrect?

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a

Methane does not react with chlorine in the dark 

b

Photobromination of 2 – methyl propane gives a mixture of 1 – bromo – 2- methyl propane and

2 – bromo – 2 – methyl propane in the ratio 9 : 1

c

The chlorination of methane may be limited almost entirely to mono chlorination if methane is

taken in large excess amount as compared to chlorine  

d

Fluorination of methane required the use of light or heating to a high temperature. 

answer is B.

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Detailed Solution

(A) In the presence light, Cl2 dissociates to give 2Cl radicals which react with CH4 via free

radical mechanism.   

(B) Br radical being less reactive is less influenced by the probability factor. The bromination

primarily depends on the reactivity of H atom which is 3° > 2° > 1°

(C) If methane is not in excess,CH2Cl2 , starts forming if the concentration of CH3Cl becomes more than that of CH4. This is contain used and thus CHCl3 and CCl4 may also be formed.

(D The reaction between CH4 and F2 is very vigorous. It can take place even in the dark or at room temperature. 

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