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Which of the following statement(s) is/are correct?

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$Ni (CO)_{4}$ 4 is diamagnetic and $s p^{3}$ hybridised

Complex ion ${[Cu (CN)_{4}]}^{3 -}$ is paramagnetic and ${Cu}^{+}$ ion is $d s p^{2}$ hybridised

${[{MnBr}_{4}]}^{2 -}$ ion is paramagnetic and $s p^{3}$ hybridised

Vaska's Catalyst i.e. $[IrCl (CO) {({PPh}_{3})}_{2}]$ is diamagnetic and ${Ir}^{+}$ ion is $d s p^{2}$ hybridised

answer is A.

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Detailed Solution

$[{Cu}^{+ 1} {({CN}_{4}]}^{3 -} \Rightarrow s p^{3}$ tetrahedral, diamagnetic.

Because there are no unpaired electrons, it is diamagnetic.

The compound's geometry is tetrahedral, and the hybridisation is $s p^{3}$ .

Vaska's complex aided in the development of a conceptual framework for homogeneous catalysis.

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