Which of the following statements is/are correct?

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${SO}_{4}^{2 -} = {NO}_{3}^{-} = I_{3}^{-} = {XeF}_{5}^{-}$ (dipole moment}

$p π - d π$ bond is present in both ${POCl}_{3}$ and ${XeO}_{3}$

$MnO$ is a basic oxide

${HClO}_{4} > {HClO}_{3} > {HClO}_{2}$ (acidic strength)

answer is A.

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Detailed Solution

${SO}_{4}^{2 -} = {NO}_{3}^{-} = I_{3}^{-} = {XeF}_{5}^{-}$ (dipole moment) :- All the S−O bond length are equal, and shorter than expected. This is due to delocalization of electrons (resonance).

$p π - d π$ bond is present in both ${POCl}_{3}$ and ${XeO}_{3}$ :- Xenon trioxide is formed on hydrolysis of xenon hexafluoride and the electronic configuration of xenon is $n s^{2} n p^{6}$ where d-orbital is vacant and thus involved in the hybridisation and the structure of xenon trioxide in the structure of xenon trioxide, it has three $p π - d π$ bonds

$MnO$ is a basic oxide:- In MnO, the oxidation state of manganese is +2 which means the oxidation state is low so it is a basic oxide.

${HClO}_{4} > {HClO}_{3} > {HClO}_{2}$ (acidic strength):- And electronegativity of chlorine in turn is directly proportional to the oxidation state of chlorine.As the number of oxygen atoms attached to chlorine increases, acid strength increase.

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