Which of the following statements is/are correct?

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The electronic configuration of $C r$ is $[A r] 3 d^{5} {4s}^{1}$ (atomic number of Cr is 24)

The magnetic quantum number may have a negative value.

In silver atom, 23 electrons have a spin of one type and 24 of the opposite type (atomic number of Ag is 47).

The oxidation state of nitrogen in $H N_{3}$ is -3.

answer is A, B, C.

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Detailed Solution

$\begin{array}{l} (a, b, c) C r (Z = 24) \\ [A r] 3 d^{5} 4 s^{1} \end{array}$
This is because $d^{5}$ is a more stable half –filled configuration Reasons for the stability of half-filled and fully filled orbitals are symmetry and exchange energy. For every value of $l$ , m can be from - $l$ to + $l$ through 0.
$A g (z = 47)$
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{1} 4 d^{10}$
23 electrons have a spin of one type and 24 of the opposite type.