Which of the following statements is not correct?

Additionally, the bicarbonate ion is larger than the carbonate ion in size. As a result, sodium carbonate will have greater packing efficiency than sodium bicarbonate. Therefore,${\mathrm{Na}}_2{\mathrm{CO}}_3$ will require more energy to disrupt than${\mathrm{NaHCO}}_3$ . As a result,${\mathrm{Na}}_2{\mathrm{CO}}_3$  is less water-soluble than${\mathrm{NaHCO}}_3$.${\mathrm{NaHCO}}_3$ is less soluble as compared to ${\mathrm{Na}}_2{\mathrm{CO}}_3$.