Which of the following statements is not correct for the reaction, $4 A + B \to 2 C + 2 D$

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The rate of formation of D is one - half of the rate of consumption of A

The rate of appearance of C is one - half the rate of disappearance of B

The rate of disappearance of B is one - fourth of the rate of disappearance of A

The rates of formation of C and D are equal

answer is A.

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Detailed Solution

$4 A + B \to 2 C + 2 D$

$- \frac{d [A]}{dt} = - \frac{d [B]}{d t} = + \frac{d [C]}{d t} = + \frac{1}{2} \frac{d [D]}{d t}$ $\frac{1}{4} (d i s a p p e a r a n c e o f A) = d i s a p p e a r a n c e o f B$

$\frac{1}{2} (a p p e a r a n c e o f C)$

$\frac{1}{2} (a p p e a r a n c e o f D)$

By comparing above information, answer can be solved.

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