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two ions A⁺ and B^– have radii 88 pm and 200 pm respectively. In the close packed crystal of compound AB, the coordination number of A⁺ is 6

in CsCl crystal, edge length is 404 pm. The distance between the nearest neighbours is 350 pm.

due to Frenkel defect, the density of the ionic solids does not change

the volume of atoms present in a face centered cubic unit cell of a metal (r is atom radii) is $\frac{16}{3} {πr}^{3}$

answer is A, B, C, D.

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Detailed Solution

A) two ions A⁺ and B^– have radii 88 pm and 200 pm respectively. In the close packed crystal of compound AB, the coordination number of A⁺ is 6

B) $r_{c} / r_{a} = 0.44, C . N = 6; CsCl - BCC :$
$b / w 2 atoms = 2 r = 2 (\sqrt{3} a / 4) = 350$

C) Due to Frenkel defect, the density of the ionic solids does not change

D) $FCC : Z = 4; 4 \times \frac{4}{3} π r^{3}$

the volume of atoms presents in a face centered cubic unit cell of a metal (r is atom radii) is $\frac{16}{3} {πr}^{3}$

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