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Which of the following the other side in the right - angled ∆PQR, where ∠Q = 90°, QR = 4 cm and PR = 6 cm?

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3.47

4.47

6.47

5.47

answer is B.

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Detailed Solution

Given, ∠Q = 90°, QR = 4 cm and PR = 6 cm.
According to the given information, a right angle is at Q. Therefore sides are QR and QP.
So according to Pythagoras theorem,

PR_{}^{2} = QR_{}^{2} + QP_{}^{2}

.
Therefore,

QP = \sqrt{PR^{2} - QR^{2}}

= \sqrt{6^{2} - 4^{2}}

= 4.47
Therefore the sides are 10cm, 8cm, 6cm.
Hence option 2 is correct.

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