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Q.

Which of the following transformations reduce the

 differential equation  dzdx+zxlogz=zx2(logz)2into the form 

dudx+P(x)u=Q(x)

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a

u=logx

b

u=(logz)1

c

u=(logz)2

d

u=e2

answer is C.

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Detailed Solution

we have, 

1z(logz)2dzdx+1x×1logz=1x2

Putting 1logz=uand 1z(logz)2dzdx=dudx, we get 

dudx+ux=1x2 

 dudx+1xu=1x2 or , dudx+P(x)u=Q(x),

P(x)=1x and Q(x)=1x2

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