Which of the following transition will emit maximum energy in hydrogen atom?

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$4 f \to 2 s$

All have same energy

$4 p \to 2 s$

$4 d \to 2 p$

answer is D.

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Detailed Solution

Energy of all (s, p, d, f) subshells present in the same orbit in a hydrogen atom have same energy because they are degenerate orbitals.
So, energy emission in 4f→2s, 4d→2p, 4p→2s transitions have same energy because all these transition are from orbit 4 to orbit 2.

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