Which of the following would weigh the highest?

$2\mathit{ moles}$ of $\mathit{CaC}{O}_3$ weigh the highest.
According to the mole concept, ⇒$1\mathit{ mole }=\mathit{ molecular}\mathit{ }\mathit{weight}\mathit{ }\mathit{in}\mathit{ }\mathit{gram}$.

 ⇒$\mathit{Molecular}\mathit{ }\mathit{weight}\mathit{ }\mathit{of }{C}_{12}{H}_{22}{O}_{11} = 12\times 12+22\times 1+11\times 16$
$= 342\mathit{ g}$

⇒$\mathit{Molecular}\mathit{ }\mathit{weight}\mathit{ }\mathit{of C}{O}_2 =12+2\times 16$
$= 44\mathit{ g}$

⇒$\mathit{Molecular}\mathit{ }\mathit{weight}\mathit{ }\mathit{of CaC}{O}_3=40+12+3\times 16$
$=100\mathit{ g}$

⇒$\mathit{Molecular}\mathit{ }\mathit{weight}\mathit{ }\mathit{of }{H}_{2}O=16+2\times 1$
$=18\mathit{ g}$
 

$\mathit{Weight}\mathit{ }of\mathit{ }a\mathit{ }\mathit{sample}\mathit{ }\mathit{in}\mathit{ }\mathit{gram }=\mathit{ number}\mathit{ }\mathit{of}\mathit{ }\mathit{moles }\times \mathit{ molar}\mathit{ }\mathit{mass }$

Therefore for the give compounds the weight can be calculated as 
1) $0.2\mathit{ moles}\mathit{ }\mathit{of }{C}_{12}{H}_{22}{O}_{11} \mathit{}=0.2\times 342$
$=68.4\mathit{ gm}$ 

2) $2\mathit{ moles}\mathit{ }\mathit{of C}{O}_2=2\times 44$
$=88\mathit{ gm }$

3) $2\mathit{ moles}\mathit{ }\mathit{of CaC}{O}_3=2\times 100$
$=200\mathit{ gm }$

4) $10\mathit{ moles}\mathit{ }\mathit{of }{H}_{2}O=10\times 18$
$=180\mathit{ gm}$ 

Therefore, $2\mathit{ moles}$ of $\mathit{CaC}{O}_3$​ weighs more than other compounds.