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Which of the following $d - orbital$ s takes part in ${sp}^{3} d$ hybridization?

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$d_{xy}$

$d_{yz}$

$d_{z^{2}}$

$d_{zx}$

answer is C.

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Detailed Solution

$[{sp}^{3} d - s, p_{x}, p_{z}, d_{z^{2}}]$
The linear combination of a 4s−orbital with three 4p−orbitals (4p_x, 4p_y, &4p_z) & one 3d−orbital (3 $d_{z^{2}}$ )results in five sp³d-orbitals.

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