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Which of the given values of x and y make the following pairs of matrices equal $[\begin{array}{cc} 3 x + 7 & 5 \\ y + 1 & 2 - 3 x \end{array}] = [\begin{array}{cc} 0 & y - 2 \\ 8 & 4 \end{array}]$

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$x = \frac{- 1}{3}, y = 7$

Not possible to find

$y = 7, x = \frac{- 2}{3}$

$x = \frac{- 1}{3}, y = \frac{- 2}{3}$

answer is B.

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Detailed Solution

Let $A = [\begin{array}{cc} 3 x + 7 & 5 \\ y + 1 & 2 - 3 x \end{array}] = [\begin{array}{cc} 0 & y - 2 \\ 8 & 4 \end{array}]$

On comparing, $3 x + 7 = 0 \Rightarrow x = - 7 / 3$ and $2 - 3 x = 4 \Rightarrow x = - 2 / 3$

Since value of x is not unique, so it is not possible to find

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