Which one has a higher electrical resistance, a $100\mathit{ watt}$ bulb or a $60\mathit{ watt}$ bulb?

The power required by the electrical appliance to work is inversely proportional to the electrical resistance. 
$\mathrm{P}={\mathrm{V}}^2/\mathrm{R}$
or
$\mathrm{R}={\mathrm{V}}^2/\mathrm{P}$
Here
$\mathrm{R}=$ resistance
$\mathrm{V}=$ voltage
$\mathrm{P}=$power of the bulb
Since the voltage is constant:
${=>\mathrm{R}}_{100}={\mathrm{V}}^2/100$ and 
${=>\mathrm{R}}_{60}={\mathrm{V}}^2/60$
${=>\mathrm{R}}_{60}>{\mathrm{R}}_{100}$

Hence, The $60 \mathrm{watt}$ bulb shows high electrical resistance.