Which one is the best method of reducing 3-bromopropanal to 1-bromopropane?
$B r C H_{2} C H_{2} C H O \to B r C H_{2} C H_{2} C H_{3}$

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None of the two

Clemmensen reduction

Wolf-Kishner reduction

Either of the two

answer is B.

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Detailed Solution

Explanation:

To reduce 3-bromopropanal ($ BrCH_2CH_2CHO $) to 1-bromopropane ($ BrCH_2CH_2CH_3 $), we need to reduce the aldehyde group ($ -CHO $) to a methyl group ($ -CH_3 $) while retaining the bromine atom in the compound.

Clemmensen Reduction:

The Clemmensen reduction involves using zinc amalgam ($ Zn-Hg $) and concentrated hydrochloric acid ($ HCl $).
This method is particularly effective for reducing aldehydes and ketones to the corresponding hydrocarbons while retaining halogen atoms in the molecule.
It is ideal for reducing $ BrCH_2CH_2CHO $ to $ BrCH_2CH_2CH_3 $.

Answer: The best method to reduce 3-bromopropanal to 1-bromopropane is Clemmensen reduction.