Which one is the Swartz reaction from the following

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${CH}_{3} Br + Nal \overset{acetone}{⟶} {CH}_{3} l + NaCl$

${CH}_{3} Br + Nal \overset{acetone}{⟶} {CH}_{3} l + NaBr$

${CH}_{3} Br + AgF ⟶ {CH}_{3} F + AgBr$

$2 {CH}_{3} Cl + 2 Na \overset{Dry ether}{⟶} {CH}_{3} - {CH}_{3} + 2 NaCl$

answer is C.

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Detailed Solution

When alkyl bromide or iodide are treated with metallic fluorides like AgF, HgF₂, etc., they form alkyl fluoride.
This reaction is called Swarts reaction and is an important method for the preparation of fluoroalkanes.
CH₃Br + AgF → CH₃F + AgBr
It is a type of halogen exchange reaction.

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