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Which one of the following alcohol can form alkyl halide with conc. HCl

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${({CH}_{3})}_{3} COH$

${({CH}_{3})}_{2} CHOH$

${CH}_{3} {CH}_{2} OH$

${({CH}_{3})}_{2} {CHCH}_{2} OH$

answer is B.

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Detailed Solution

${RCH}_{2} OH (1^{0}) & R_{2} CHOH (2^{0}) require anhydrous {ZnCl}_{2} along with conc . HCl .$ $R_{3} COH (3^{0}) can give R_{3} CCl with Conc . HCl even in absence of an . {ZnCl}_{2}$

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