Which one of the following compounds has the electron pair geometry as the trigonal bipyramidal with three equatorial positions occupied by lone pairs of electrons?

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${CH}_{3} - Mg - Br$

${XeF}_{2}$

$[Pt {({NH}_{3})}_{2} {Cl}_{2}]$

${AlCl}_{3}$

answer is B.

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Detailed Solution

Trigonal Bipyramidal Geometry with Three Lone Pairs

The compound with trigonal bipyramidal electron pair geometry and three equatorial positions occupied by lone pairs is the triiodide ion (I₃^-).

Explanation:

In I₃^-, the central iodine atom forms bonds with two other iodine atoms.
It has five regions of electron density: two bonding pairs and three lone pairs.
According to VSEPR theory, the three lone pairs occupy the equatorial positions in the trigonal bipyramidal geometry to minimize repulsion.
The two iodine atoms occupy the axial positions.
The molecular shape is linear, but the electron pair geometry is trigonal bipyramidal with three lone pairs in the equatorial positions.

Correct Answer: I₃^- (triiodide ion)

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