Which one of the following electronic configuration of an atom has the highest ionization energy?

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$1 s^{2}, 2 s^{2} 2 p^{6}$

$\begin{aligned} 1 s^{2}, 2 s^{2} 2 p^{3} \end{aligned}$

$\begin{aligned} 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{1} \end{aligned}$

$1 s^{2}, 2 s^{2} 2 p^{5}$

answer is C.

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Detailed Solution

The electronic configuration of an atom has the highest ionization energy is Neon( $1 s^{2} 2 s^{2} 2 p^{6}$ )

The electrical arrangement of neon is $1 s^{2} 2 s^{2} 2 p^{6}$ . Neon is a Nobel gas.

In their atoms' outermost shells, there are 8 electrons.

Neon does not want to loose an electron and have its stability disrupted. As a result It has the highest ionization energy due to which it will take a tremendous amount of energy to remove one of its electrons.

Hence Neon has the highest ionization energy

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