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Which one of the following has maximum number of atoms?

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1 g of Ag(s) [Atomic mass of Ag = 108]

1 g of Mg(s) [Atomic mass of Mg = 24]

1g of O₂(g) [Atomic mass of O = 16]

1 g of Li(s) [Atomic mass of Li = 7]

answer is D.

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Detailed Solution

One gram atom of any element contains Avagadro's number $(N_{0})$ of atoms;

One gram of each atom contain

$\begin{array}{l} Li = \frac{1}{7} \times N_{0} \\ Mg = \frac{1}{24} \times N_{0} \\ O = \frac{1}{16} \times N_{0} \\ Ag = \frac{1}{108} \times N_{0} \end{array}$

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