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Q.

Which one of the following has sp3,sp2,sp hybrid orbitals in the ration  6:3:2?

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a

H3C−CH2−C≡C−CH=CH2

b

H3C−CH=CH−CH2−C≡C−CH3

c

H3C−CH=CH−C≡CH

d

H3C−CH=CH−CH2−C≡CH

answer is A.

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Detailed Solution

H3C−CH=CH−CH2−C≡C−CH3 sp3      sp2     sp2   sp3   sp   sp    sp3  3sp3=12 2sp2=6 2sp=4

 

 

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