Which one of the following is square planar in structure and has diamagnetic property ?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

[Ni(CN)₄]^2–

[Ni(CO)₄]

[NiCl₄]^2–

[Ni(H₂O)₆]²⁺

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In [Ni(H₂O)₆]²⁺, the oxidation state of Ni is +2 and its outer electronic configuration becomes 3d⁸ 4s⁰. Electrons remain unpaired in 3d-subshell of Ni because water acts as a weak ligand.

In [Ni(CO)₄], oxidation state of Ni is 0 and when CO (strong ligand) approaches Ni, then all electrons from 4s subshell also gets paired in 3d. As a result, complex becomes diamagnetic but it forms a tetrahedral complex.

In [Ni(CN)₄]^2-, the oxidation state of Ni is +2 and electrons of 3d-subshell gets paired when cyanide ion (strong ligand) approaches. The hybridization of the complex becomes dsp², has square planar geometry and is diamagnetic.

In [NiCl₄]^2-, oxidation state of Ni is +2 and the electrons in 3d-subshell remain unpaired because chloride ion is a weak field ligand.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th