Q.

Which one of the following is square planar in structure and has diamagnetic property ?

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a

[Ni(CN)4]2–

b

[Ni(CO)4]

c

[NiCl4]2–

d

[Ni(H2O)6]2+

answer is C.

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Detailed Solution

In [Ni(H2O)6]2+, the oxidation state of Ni is +2 and its outer electronic configuration becomes 3d8 4s0. Electrons remain unpaired in 3d-subshell of Ni because water acts as a weak ligand.

In [Ni(CO)4], oxidation state of Ni is 0 and when CO (strong ligand) approaches Ni, then all electrons from 4s subshell also gets paired in 3d. As a result, complex becomes diamagnetic but it forms a tetrahedral complex.

In [Ni(CN)4]2-, the oxidation state of Ni is +2 and electrons of 3d-subshell gets paired when cyanide ion (strong ligand) approaches. The hybridization of the complex becomes dsp2, has square planar geometry and is diamagnetic.

In [NiCl4]2-, oxidation state of Ni is +2 and the electrons in 3d-subshell remain unpaired because chloride ion is a weak field ligand.

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