Which one of the following is the correct order of spin-only magnetic moment for the given complexes?

${\mathrm{Cl}}^{-}\to \mathrm{l}$ Weak field ligand (no pairing occurs)
${\mathrm{H}}_2\mathrm{O}\to \mathrm{I}$Weak field ligand (no pairing occurs)
${\mathrm{CN}}^{-}\to$ Strong field ligand (pairing occurs)
$Mn=\left[\mathrm{Ar}\right]3d^{5}4s^2$
${\mathrm{Mn}}^{3+}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^4\text{no. of unpaired}{\mathrm{e}}^{-}=4$
$\mathrm{CO}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^{7}4{\mathrm{s}}^2$
${\mathrm{Co}}^{2+}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^{7}4{\mathrm{s}}^{\circ }\text{no. of unpaired}{\mathrm{e}}^{-}=3$

$\mathrm{Fe}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^{6}4{\mathrm{s}}^2$
${\mathrm{Fe}}^{3+}=\left[\mathrm{Ar}\right]3{\mathrm{d}}^5$

On pairing

no. of unpaired e– = 1
So, spin magnetic moment =
${\left[{\mathrm{MnCl}}_6\right]}^{3-}>{\left[\mathrm{Co}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}>{\left[\mathrm{Fe}\right(\mathrm{CN}{)}_6]}^{3-}$