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Which one of the following reactions of Xenon compounds is not feasible?

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$2 {XeF}_{2} + 2 H_{2} O ⟶ 2 Xe + 4 HF + O_{2}$

$3 {XeF}_{4} + 6 H_{2} O \to Xe + {XeO}_{3} + 12 HF + 1 .5 O_{2}$

${XeO}_{3} + 6 HF ⟶ {XeF}_{6} + 3 H_{2} O$

${XeF}_{6} + RbF ⟶ Rb ({XeF}_{7})$

answer is A.

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Detailed Solution

${XeO}_{3} + 6 HF ⟶ {XeF}_{6} + 3 H_{2} O$

This reaction is not feasible because the products again react to give reactants back. All the xenon fluorides easily undergo hydrolysis and give xenon oxides.

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