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Which one of the following set of quantum numbers is not possible for any of the19 electrons in the ground state of an atom with atomic number 19 ?

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n = 2, l = 0, m = 0

n = 2, l = 1, m = 0

n = 3, l = 1, m = – 1

n = 3, l = 2, m = 2

answer is D.

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Detailed Solution

K(Z = 19)…1s²2s²2p⁶3s²3p⁶4s¹

$\begin{matrix} 1 s^{2} & 2 s^{2} & 2 p^{6} & 3 s^{2} & 3 p^{6} & 4 s^{1} \\ (1, 0) & (2, 0) & (2, 1) & (3, 0) & (3, 1) & (4, 0) \end{matrix}$

Thus n = 3, l = 2 is not possible

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