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Which one of the following will have the largest number of atoms?

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100 g of He

100 g of Na

100 g of Li

100 g of Al

answer is A.

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Detailed Solution

N o . o f a t o m s (N) = \frac{G i v e n m a s s (m)}{G i v e n a t o m i c m a s s (M)} \times A v a g a d r o N o . (N_{A})

1) $N_{H e} = \frac{100}{4} \times N_{A} = 25 N_{A}$

2) $N_{N a} = \frac{100}{23} \times N_{A} = 4.34 N_{A}$

3) $N_{L i} = \frac{100}{7} \times N_{A} = 14.28 N_{A}$

4) $N_{A l} = \frac{100}{27} \times N_{A} = 3.70 N_{A}$

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