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Which one of the given interchange in signs and numbers would make given equation correct? $16 - 8 \times 16 - 2 \div 4 + 3 = 15$

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$+ & \div & 3 & 4$

$\times & - & 16 & 4$

$- & \div & 8 & 2$

$\times & - & 16 & 2$

answer is C.

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Detailed Solution

$\begin{array}{l} 16 \div 2 \times 16 \div 8 - 4 + 3 = 15 \\ \Rightarrow 8 \times 2 - 4 + 3 = 15 \\ \Rightarrow 16 - 4 + 3 = 15 \\ \Rightarrow 12 + 3 = 15 \\ \Rightarrow 15 = 15 \end{array}$

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