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Q.

:Which one of the lanthanoids given below is the most stable in divalent form?

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a

Ce (Atomic Number 58)

b

Sm (Atomic Number 62)

c

Eu (Atomic Number 63)

d

Yb (Atomic Number 70)

answer is C.

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Detailed Solution

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EM3+/M2+oEuYb0.351.05
Hence, due to more reduction potential in Eu as 
compared to Yb, it can concluded that Eu2+ is more stable than Yb2+

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