Which order is correct when the species are arranged in order of increasing average $N - O$ bond length?

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${NO}^{+}, {NO}_{3}^{-}, {NO}_{2}^{-}$

${NO}^{+}, {NO}_{2}^{-}, {NO}_{3}^{-}$

${NO}_{3}^{-}, {NO}_{2}^{-}, {NO}^{+}$

${NO}_{2}^{-}, {NO}_{3}^{-}, {NO}^{+}$

answer is D.

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Detailed Solution

${NO}^{+}, {NO}_{2}^{-}, {NO}_{3}^{-}$ order is correct when the species are arranged in order of increasing average $N - O$ bond length.
Bond order is described as the ratio of the number of bonds to the number of anti-bonds. The number of electron pairs between two atoms is often referred to as the bond order.
The average distance between the nuclei of two bound atoms in a molecule is how bond length is essentially defined. Bond length is inversely proportional to bond order, according to the relationship between the two variables.
Hence, option D is correct.