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Which pair of electrolytes give different products at anode

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1M CuSO₄ solution 1M CuCl₂ solution

1M KCl solution 1M Cu(NO₃)₂ solution

1M AgNO₃ solution 1M CuSO₄ solution

1M CuBr₂ solution 1M CuSO₄ solution

answer is A, B, D.

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Detailed Solution

$\begin{array}{ll} aq Cu {({NO}_{3})}_{2} \to O_{2}; aq {CuSO}_{4} \to O_{2} \\ aq {CuCl}_{2} \to {Cl}_{2}; aq KCl \to {Cl}_{2} \\ aq {AgNO}_{3} \to O_{2}; aq {CuBr}_{2} \to {Br}_{2} \end{array}$

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