Q.

which pair of functions is identical?

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a

sin1(sinx) and sinsin1x

b

logex2,2logex

c

 None of these 

d

logeex,elogex

answer is D.

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Detailed Solution

 Here,
 (a) sin1(sinx) is defined for xπ2,π2, while sinsin1x is defined only for x[1,1]

 (b) logeex, is defined for all x, while elogex is defined for x>0

 (c) logex2 is defined for all xR{0}, while 2logex is definedforx>0. 

Thus, none is identical.

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