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Q.

Which point is on the x-axis which is equidistant from the points (-1,0) and (5,0)?


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a

(0,0)

b

(0.2)

c

(0,3)

d

(2,0) 

answer is D.

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Detailed Solution

We have been given two points (-1,0) and (5,0).
Using the distance formula,
D=x2-x12+y2-y12
Let,
A(1,0) B=(5,0)
Let the required point be C,
We know, C is the point that is equidistant from A and B.
Also, C lies on x-axis,
So, we can say that,
C(x,0) Depending on a certain circumstance we know,
AC=CB             ........(1) Substituting x2=-1, x1=x, y2=0, and y1=0, in the formula,
AC= (1x) 2 + (00) 2 AC=x+1 (2)
Similarly,
Substituting x2=5, x1=x, y2=0, and y1=0, in the formula,
CB= (5x) 2 + (00) 2 CB=5x.(3)  From, (1),(2) and (3) x+1=5x 2x=51 2x=4 x=2  Thus, C=(2,0)
Therefore, the coordinates of point C is (2,0).
Hence, option 4 is correct.
 
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