Which set of quantum numbers Is not possible?

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$n = 5, l = 2, m_{l} = 2, m_{s} = - \frac{1}{2}$

$n = 3, l = 2, m_{l} = + 1, m_{s} = + \frac{1}{2}$

$n = 2, l = 1, m_{l} = + 1, m_{u} = - \frac{1}{2}$

$n = 4, l = 4, m_{l} = - 1, m_{n} = + \frac{1}{2}$

answer is C.

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Detailed Solution

Quantum numbers are not possible of $n = 4, l = 4, m_{l} = - 1, m_{n} = + \frac{1}{2}$ .

Zero cannot exist for the main quantum number (n). So, 1, 2, 3, 4, and so on are all permitted values for n. The angular quantum number (l) can be any integer between 0 and n minus 1. For instance, l can be 0, 1, or 2 if n is equal to 3.

Hence, option C is correct.

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