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Which statement is correct about electrolysis of CuSO₄ ?

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At cathode Cu will deposit and at anode O₂ will be produced using Pt-electrode

At cathode Cu will not deposit but Cu dissolve at anode using Cu-electrode

At cathode Cu will deposit and at anode H₂ will be produced using Cu-electrode

At cathode Cu will deposit and at anode Cu will dissolve using Cu-electrode

answer is A, D.

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Detailed Solution

Using Pt electrodes

$C u S O_{_{4}} \to C u^{2 +} + S O_{4}^{2 -}$

$H_{2} O \to H^{+} + H O^{-}$

At cathode : $C u^{2 +} + 2 e^{-} \to C u$

Anode : $4 H O^{-} \to 2 H_{2} O + O_{2} + 4 e^{-}$

Products are Cu and O₂

Using Cu electrodes

Anode : $C u \to C u^{2 +} + 2 e^{-}$

Cathode : $C u^{2 +} + 2 e^{-} \to C u$

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