Which statement is correct at 25° C and 1 atm pressure?

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${ΔG}_{f}^{\circ}$ for $Hg (l) = 0 kJ \cdot {mol}^{- 1}$

${ΔH}_{f}^{\circ}$ for $I_{2} (g) = 0 kJ \cdot {mol}^{- 1}$

${ΔH}_{f}^{\circ}$ for $H_{2} O (l) = 0 kJ \cdot {mol}^{- 1}$

$S^{\circ}$ for $O_{2} (g) = 0 J \cdot {mol}^{- 1} K^{- 1}$

answer is A.

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Detailed Solution

At room temperature (25° C) and 1 atm pressure the gibbs free energy for the lead is $0 kJ \cdot {mol}^{- 1}$ .

So the correct statement for the given conditions is,

${ΔG}_{f}^{\circ}$ for $Hg (l) = 0 kJ \cdot {mol}^{- 1}$

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