Which statement is correct at 25° C and 1 atm pressure?

At room temperature (25° C) and 1 atm pressure the gibbs free energy for the lead is $0 \mathrm{kJ}\cdot {\mathrm{mol}}^{-1}$.

So the correct statement for the given conditions is,

${\mathrm{\Delta G}}_{\mathrm{f}}^{\circ }$ for $\mathrm{Hg}\left(\mathrm{l}\right)=0 \mathrm{kJ}\cdot {\mathrm{mol}}^{-1}$