Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Which term of the A.P. 3, 15, 27, 39, ... will be 132 more than its $5 4^{th}$ term?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given A.P. is A.P. 3, 15, 27, 39, ...
We know the formula,

a n = a + n − 1 d

Where,
The first term is a.
The common difference is d.
The number of terms are n.
According to the question,
The common difference will be,

d = a 2 − a 1 ⇒ d = 15 − 3 ⇒ d = 12

Now,

a 54 = a 1 + 54 − 1 d ⇒ a 54 = 3 + 5312 ⇒ a 54 = 639

Also,

a n = a 54 + 132 ⇒ a n = 639 + 132 ⇒ a n = 771

Again,

771 = 3 + n − 1 12 ⇒ 771 − 3 12 = n − 1 ⇒ 64 + 1 = n ⇒ n = 65

So, the term that is 132 more than the

54^{th}

term is the

65^{th}

term.
Hence, option 4 is correct.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE