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Which term of the AP 2, 11, 20, 29…… is 290?

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32

33

30

35

answer is D.

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Detailed Solution

Here a = 2 and d = 11 – 2 = 9
Let the given AP contain n terms.
T_n = 290
=> a + (n – 1)d = 290
=> 2 + (n – 1)9 = 290
=> 2 + 9n – 9 = 290
=> 9n = 297
=> n = 33
Thus, the 33 term of the AP is 290.

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