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Which term of the sequence $3, 8, 13, 18, . . . . . . . .$ is $498$ .

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9 5^{th}

10 0^{th}

10 2^{th}

10 1^{th}

answer is B.

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Detailed Solution

Given the sequence

3, 8, 13, 18, . . . . . . . .

We have to find which term of the sequence is 498.
Here we have,

a = 3, l = 498, d = 5

.
Thus,

l = a + (n - 1) d

\Rightarrow 498 = 3 + (n - 1) 5

\Rightarrow 498 - 3 = (n - 1) 5

\Rightarrow 495 = (n - 1) 5

\Rightarrow \frac{495}{5} = n - 1

\Rightarrow 99 = n - 1

∴ n = 99 + 1

∴ n = 100

Therefore, the

100^{th}

term is

498

.
Hence, option 2 is correct.

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