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Q.

Which term of the sequence 72, 70, 68, 66. . . . . is 40?


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a

13

b

15

c

17

d

18 

answer is C.

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Detailed Solution

Here, we are given the sequence as 72, 70, 68, 66 . . . . . . . . . .
d = 70-72 = -2.
a = 72.
Now, we need to find the term whose value is 40 which means we need to find n if an=40.
an=a+(n−1)d.
So putting in the values we get:
40=72+(n−1)(−2)
⇒40=72−2n+2
⇒2n=34
⇒n=17
Here 17th term of the given AP is 40.
 
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