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Q.

While boarding an airplane, a passenger got hurt. The pilot showing promptness and concern, made arrangements to hospitalize the injured and so the plane started late by 30 minutes to reach the destination, 1500 km away in time, the pilot increased the speed by 100 km/h. Find the original speed of the plane.


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a

500 km/h

b

1000 km/h

c

1500 km/h

d

225 km/h 

answer is A.

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Detailed Solution

Given:
The plane started late by 30 minutes to reach the destination, 1500 km away, in time, the pilot increased the speed by 100 km/hr.
Total distance = 1500 km
Assume the original speed of the plane to be x km/h.
Then the increased speed of the plane will be (x+100) km/h.
Time taken t 1   by the plane to cover a distance 1500 km   with a speed of x km/h  , Time  =  Distance   Speed  t 1 = 1500 x   Time taken  t 2  by the plane to cover a distance of 1500 km with a speed of (x+100) km/h.   Time  =  Distance   Speed  t 2 = 1500 x+100   Therefore, according to the given conditions
1500 x 1500 x+100 = 30 60  
1500 x 1500 x+100 = 1 2 1500x+1500001500x x(x+100) = 1 2 300000 x 2 +100x =1 x 2 +100x300000 =0  
x 2 +600x500x300000=0 x(x+600)500(x+600)=0 (x+600)(x500)=0  
Either x+600=0   or x500=0  
Therefore, the possible values of x are, x=600   or x=500  .
Since x represents speed, hence it cannot be negative,
Therefore, the original speed of the plane is 500 km/h.
Hence, the correct option is 1.
 
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