While charging the lead storage battery 

The cell reactions taking during charging of lead storage battery are 

$$\begin{gathered} Anode:\hspace{0.17em}PbS{O}_4^{ }+\hspace{0.17em}2e^{-}\to Pb +\hspace{0.17em}S{O}_4^{2-} \\ Cathode :\hspace{0.17em}PbS{O}_4+\hspace{0.17em}2 H_{2}O\hspace{0.17em}\to Pb{O}_2+\hspace{0.17em}S{O}_4^{2-}+\hspace{0.17em}4 H_{ }^{+}+\hspace{0.17em}2e^{-} \end{gathered}$$

Hence PbSO₄ at anode is reduced to Pb